what is the change in enthalpy (delta H) of this reaction:?
The reaction 125 ml of .35 M HCl is reacted in a calorimeter with an excess of NaOH according to the following reaction: HCl + NaOH -> NaCl + H2O. The calorimeter contains 1 kg of water original at 25.7 degrees celcius . after the reaction , the water has a temperature of 29.1 degrees celcius . what is the delta H (change in enthalpy) of this reaction expressed in KJ/mole?>
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- _____Is treated not reacted _____HCl ___+___NaOH ---------------> H2O ___+___ NaCl____dHneut = ??kJ/mole heat released = 4184kJ/kgC * 1 kg * (29.1 -25.7)C = ?? moles HCl = 0.125 liters * 0.35 moles/liter = ?? moles dHneut = - (?? kJ released)/??moles HCl = - ?? kJ/mole Plug and SOLVE Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem.
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